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JimmyWork
Power Participant
Power Participant

Create sharing link for a file or folder (Wont work with dynamic data?)

Hi 

 

Im trying to create a sharing link for a file using the "Create sharing link for a file or folder"

Everything works if i select the Site address and Library Name manually. But if use dynamic content in the Library name it will fail, even if the name is displayed exactly the same.

 

How can i use dynamic content in Library name? If i use the "create file" and use dynamic content in library then no issue, but the "Create sharing link for a file or folder" just dont allow me to use dynamic content in Library Name?

 

With dynamic content in Library name

2019-11-06 16_28_03-Run History _ Power Automate.png

 

Without dynamic content in Library name

2019-11-06 16_27_31-Run History _ Power Automate.png

 

1 ACCEPTED SOLUTION

Accepted Solutions

@v-alzhan-msft 

By getting the list ID you can use this as a dynamic content and make it work.

 

Send an Http Request:

_api/web/lists/GetByTitle('Name of the list')?$select=id

View solution in original post

3 REPLIES 3
v-alzhan-msft
Community Support
Community Support

Hi @JimmyWork ,

 

I have made a test on my side and the dynamic content in the Library name in the "Create sharing link for a file or folder" action is not supported in microsoft flow currently, if you would like the dynamic content in the Library name in the "Create sharing link for a file or folder" action to be supported in microsoft flow, please submit an idea to flow ideas fourm:

https://powerusers.microsoft.com/t5/Power-Automate-Ideas/idb-p/FlowIdeas

 

Best regards,

Alice       

 

Community Support Team _ Alice Zhang
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

@v-alzhan-msft Thank you for the answer.

 

I belive it works with the ListID and not ListName, i will test a bit more later today.

@v-alzhan-msft 

By getting the list ID you can use this as a dynamic content and make it work.

 

Send an Http Request:

_api/web/lists/GetByTitle('Name of the list')?$select=id

View solution in original post

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