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Damo_R
Frequent Visitor

Format decimal numbers

I am trying to format the data of a calculated field within the flow to send in an email to show 2 decimal places. has anyone acheived this? 

 

I have tried both Text and Round and several iterations of these functions and they come back as invalid templates. 

 

Can anyone shine any light on this? 

 

Capture.JPG

 

the value from the column is 1.50000000000 i only want to see 1.5

1 ACCEPTED SOLUTION

Accepted Solutions
efialttes
Community Champion
Community Champion

As far as I know, math functions currently supported in Microsoft FLow as "expressions" are the ones defined here:

https://docs.microsoft.com/en-us/azure/logic-apps/logic-apps-workflow-definition-language

 

I guess you can multiply by 100, convert into integer, get back to float and divide into 100; but I haven't tested myself; so unsure if both float() and int() accepts non-string parameters

 

Hope this helps

 

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View solution in original post

22 REPLIES 22
efialttes
Community Champion
Community Champion

As far as I know, math functions currently supported in Microsoft FLow as "expressions" are the ones defined here:

https://docs.microsoft.com/en-us/azure/logic-apps/logic-apps-workflow-definition-language

 

I guess you can multiply by 100, convert into integer, get back to float and divide into 100; but I haven't tested myself; so unsure if both float() and int() accepts non-string parameters

 

Hope this helps

 

Did I make your day? If so, mark my response as 'Solution' !!!

También escribo sobre Power Automate en este Blog y en Twitter

@efialttes thank you so much for your repsponse and the link you provided. With a little reading and some trial and error i have come up with the following:

 

if(or(greater(body('Create_item')?['Days_x0020_Total'], string (10)),equals(body('Create_item')?['Days_x0020_Total'],string(10))),take(body('Create_item')?['Days_x0020_Total'],4),take(body('Create_item')?['Days_x0020_Total'],3))

 

This basically looks at the value in the total days field and determines if it is greater or equal to 10, if yes then it will produce 4 place and if no it will produce 3 places.

 

works a treat

efialttes
Community Champion
Community Champion

@Damo_R

You are welcome. Thanks for sharing!

Did I make your day? If so, mark my response as 'Solution' !!!

También escribo sobre Power Automate en este Blog y en Twitter

There's still no generalized rounding solution in Flow, which means building solutions specific to your data. Here's an approach I took when I needed to round from three decimals (#.###) to two (#.##) for display purposes. Fortunately, I knew I'd always be getting data in a #.### format, but you could pretty easily extend this to find the decimal place if the number of places to the left of the decimal was unknown.

 

if(contains('56789', substring(string(triggerBody()['number']),4,1)),substring(string(add(triggerBody()['number'],0.01)),0,4),substring(string(triggerBody()['number']),0,4))

Anonymous
Not applicable

I just used your suggestion to round the result of my division formula:

Original expression:

div(variables('Sum'),5)

Which returned the full result, i.e 1.6666666 or similar.

 

I formatted it to 1 decimal using this expression:

div(float(int(mul(div(variables('Sum'),5),10))),10)

 

that is

  • take result from division
  • multiple by 10
  • converting to int
  • converting to float (else it became an integer result)
  • dividing by 10

 

Thanks for the hint!

It was not as simple, because int() and float() only accept string arguments. So you get a run-time error like this:

 

InvalidTemplate. Unable to process template language expressions in action 'Rounded' inputs at line '1' and column '2484': 'The template language function 'int' was invoked with a parameter that is not valid. The value cannot be converted to the target type.'.
 
On top of that, the  int() function only accepts string representations of integer numbers - it does not accept any floating point number. So I had to turn the number to string, select the part before the '.' and pass it to  int(). Not sure if the '.' is subject to localization, which would obviously fail. 
 
This is the expression I've put into a Compose action:
div(int(first(split(string(mul(123.456, 10.0)),'.'))), 10.0)
The output was 
123.4
aCTim
New Member

Thanks to Damo_R I was able to round numbers for our case, with two numbers behind. A little bit ugly, but it works.

 

Initializing 2 variables.

variable var as string 

first(split(string(mul(123.454, 1000.0)),'.'))

(you can put your number or varible where 123.454 is)

variable varTemp as Integer

int(variables('var'))

than we go on with a condition

if

int(last(variables('var')))

equal or even to 5

 

set var to

sub(add(int(variables('varTemp')),10),int(last(string(variables('varTemp')))))

else

set var to 

sub(int(variables('varTemp')),int(last(string(variables('varTemp')))))

finally transform it to a float (int would slice the numer)

div(float(int(div(int(variables('var')),10))),100)

 

Damo_R
Frequent Visitor

Glad my efforts could help you

Here's a similar solution, but no temp variables are needed.

Uses variables('myFloat') to represent the number you want to round.

div(
add(
mul(variables('myFloat'), 1000),
sub(
if(
greaterOrEquals(
mod(mul(variables('myFloat'), 1000), 10),
5
),
10,
0
),
mod(mul(variables('myFloat'), 1000), 10)
)
),
1000
)

Or, all in one line: 

div(add(mul(variables('myFloat'),1000),sub(if(greaterOrEquals(mod(mul(variables('myFloat'),1000),10),5),10,0),mod(mul(variables('myFloat'),1000),10))),1000)

The float is multilpiled by 1000 before doing modulo to avoid tiny-fraction math errors (e.g. returning 0.00499999... instead of 0.005).

 

Using add, sub, mul, div, and mod to round a float... a reasonable workaround... XD

 

If you're looking for an expression to format for currency with a thousands separator, see my expression in another post.

nsauter23
Frequent Visitor

This can be done with the following

 

substring(string(triggerOutputs()?['body/tileValue'])),0,3)

Don't forget the decimal '.' counts as a character because this is a string not an actual intager.  It is not actual rounding, but it accomplished what I needed for my email to look cleaner. 

Anonymous
Not applicable

@StevenWade , thanks so much for sharing this. I want to limit my decimals to two points, can you please help me with what modification should I make in the expression you shared please, thanks in advance. 

Anonymous
Not applicable

@jan-dolejsi thanks for sharing. I have a requirement to limit decimal points to two, so as an example: 40.325 should result into 40.33. Can you please help me with the revised formula, thanks in advance. 

Anonymous
Not applicable

@degvalentine thanks for sharing, I used your expression for limiting decimals to two places and it seems to work well. Noticing a small issue, if the values are 2.2, 4.3 etc then the expression returns 2.2, 4.3 only but instead i want it to show 2.20, 4.30, is it possible? Please help.

Hi @Anonymous,

 

Actually, my hideous workaround is no longer needed. They added the "formatNumber" function. Please use that instead. Here's the syntax for common currency formatting (without currency symbol):

 

formatNumber(variables('myFloat), 'N', 'en-US')

 

Anonymous
Not applicable

Thanks a lot for. My field is of type number. Can u give some info on the parameter ‘N’ specified in the expression, would it help limiting decimals to two points? Thanks.

Here's the doc for all available number formatting options: https://docs.microsoft.com/en-us/dotnet/standard/base-types/standard-numeric-format-strings

Anonymous
Not applicable

Thanks @degvalentine a lot for sharing this, I was stuck with this issue since 3 days and this helped me out, keep up the good work, cheers!! 

p.s: it works great and gives me two decimal points. 

Hi @jan-dolejsi ,

 

How do I get 2 decimals instead of just one? 

 

Thank you!

@rafaelbenicio you should use the "formatNumber()" expression or the "Format Number" action.

 

Here are links to the standard formats and custom formats.

 

formatNumber(1.995,'N2') // returns "2.00"

 

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