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cgru3eejc2
Advocate IV
Advocate IV

Get List Display name

Hi,

I hava Flow where I build some reusable variables for further use in the flow:

e.g. the Site Address from the link to item value: first(split(triggerBody()?['{Link}'], '/_layouts'))

and also the ListName (split(triggerBody()?['{Path}'], '/')[1])

 

I re-use these values for other actions in the flow, e.g. in "Get item"

Listname from the URL: SiteRequests

List DisplayName: Site Requests

SNAG-0023.jpg

 

Unfortunately the ListName from the URL is not equally to the List DisplayName  which needs to be used as "List Name" in the Get Item connector.

 

 

Is there a REST API or how can I get the real Display Name from a List where the item is in?

 

Thanks for any help.

Stefan

1 ACCEPTED SOLUTION

Accepted Solutions
v-bacao-msft
Community Support
Community Support

 

Hi @cgru3eejc2 ,

 

Please try to use this method to get List Name:

17.PNG18.PNG

 

Best Regards,

Community Support Team _ Barry
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

View solution in original post

2 REPLIES 2
abm
Super User
Super User

Hi @cgru3eejc2 

 

Try using flow step Send an http request to SharePoint.

 

_api/web/lists/GetByTitle('YourSharePointListname')

 

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Thanks

 

 



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v-bacao-msft
Community Support
Community Support

 

Hi @cgru3eejc2 ,

 

Please try to use this method to get List Name:

17.PNG18.PNG

 

Best Regards,

Community Support Team _ Barry
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

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