Opposite of intersection exist in PA?

[dlprentice]

So basically the title, I do an intersection() I get the common items, all is good. Now, is there an expression to get the items that don't match or would I be forced to use some filter array actions for this?

[fchopo · Accepted solution]

Hi @dlprentice 

I guess the only solution you have is to use Filter Array action. In this sample, this filter array action is getting items that are in List2 (array) and not present in List1 (array):

You could do it for List1 and List2 in another action, and finally use a union operation to get a list of all items.

Hope it helps!

Ferran

[dlprentice]

Thank you! This works so much better than a Apply_for_each loop!

[steve_hendy]

Wish I saw this earlier, well done

[risham]

It does not work for me, instead of giving me the unique items, the flow returns all the items that are in the List 2

[ericwhitley]

Works great! Just make sure your arrays have the same structure.

[testasdfasfsafa]

I don't understand, you will still need an apply for each for each item in 1 array...

[Matt2001]

Hi, could you please explain what output-item is?