cancel
Showing results for 
Search instead for 
Did you mean: 
Reply
n1cks
Frequent Visitor

RSS (XML) to Twitter with a photo

Below is a snippet of the XML from an RSS feed. 

I would like to post a Tweet with an image. 

The link to the image is in the enclosed URL tag (replace the & with & to view the image).  

E.g.

https://scontent-ort2-2.cdninstagram.com/v/t51.2885-15/e35/83656913_122453209286778_2085275534449482...

 

I see the option to 'add dynamic content', but need help with making an expression. 

Thanks in advance. 

 

<item>

<title>This place looks amazing</title>
<link>   </link>
<dc:creator>      </dc:creator>
<pubDate>Tue, 04 Feb 2020 07:02:12 PST</pubDate>
<guid isPermaLink="true">     </guid>

<description>

This place looks amazing
</description>

<enclosure url="https://scontent-ort2-2.cdninstagram.com/v/t51.2885-15/e35/83656913_122453209286778_2085275534449482794_n.jpg?_nc_ht=scontent-ort2-2.cdninstagram.com&amp;_nc_cat=106&amp;_nc_ohc=sRbQdob1O5MAX8B1-ff&amp;oh=c3d9aa3fb45c05ca156f2c929ad9eb01&amp;oe=5EC347FA" length="0" />

<activity:object-type xmlns:activity="http://activitystrea.ms/spec/1.0/">http://activitystrea.ms/schema/1.0/photo          </activity:object-type>
						
<activity:verb  xmlns:activity="http://activitystrea.ms/spec/1.0/">http://activitystrea.ms/schema/1.0/post    </activity:verb>

<georss:featureName xmlns:georss="http://www.georss.org/georss">Bolton Abbey   </georss:featureName>
					

</item>

 

1 ACCEPTED SOLUTION

Accepted Solutions
v-bacao-msft
Community Support
Community Support

 

Hi @n1cks ,

 

The best option to extract this data is to use xpath() function to parse the feed and get the URL.

Please check this similar thread and see if it helps:

https://powerusers.microsoft.com/t5/General-Power-Automate/help-with-Xpath-and-Soap-message/td-p/322...

https://powerusers.microsoft.com/t5/Building-Flows/Iterate-XML-with-flow/m-p/163734#M16546

 

Besides, you could also use the WDL function to extract the URL, try to use the following expression:

split(split(outputs('Compose'),'<enclosure url="')[1],'" length="0" />')[0]

Image reference:

22.PNG

Hope this helps.

 

Best Regards,

Community Support Team _ Barry
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

View solution in original post

2 REPLIES 2
v-bacao-msft
Community Support
Community Support

 

Hi @n1cks ,

 

The best option to extract this data is to use xpath() function to parse the feed and get the URL.

Please check this similar thread and see if it helps:

https://powerusers.microsoft.com/t5/General-Power-Automate/help-with-Xpath-and-Soap-message/td-p/322...

https://powerusers.microsoft.com/t5/Building-Flows/Iterate-XML-with-flow/m-p/163734#M16546

 

Besides, you could also use the WDL function to extract the URL, try to use the following expression:

split(split(outputs('Compose'),'<enclosure url="')[1],'" length="0" />')[0]

Image reference:

22.PNG

Hope this helps.

 

Best Regards,

Community Support Team _ Barry
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

View solution in original post

Thanks. Helps a lot. 

 

I'm just missing the 'compose' step.  

 

Is there an expression to pull out the XML? 

 

Screenshot (4).png

 

 

Edit: 

I got this to work - my flow extracts the image URL from an RSS feed.  But it turns out, the media field in the Post a Tweet action doesn't accept image URL.  Any ideas? 

 

 

Helpful resources

Announcements
UG GA Amplification 768x460.png

Launching new user group features

Learn how to create your own user groups today!

Community Connections 768x460.jpg

Community & How To Videos

Check out the new Power Platform Community Connections gallery!

M365 768x460.jpg

Microsoft 365 Collaboration Conference | December 7–9, 2021

Join us, in-person, December 7–9 in Las Vegas, for the largest gathering of the Microsoft community in the world.

Top Solution Authors
Users online (2,255)