Hello - this might be a simple solution but it's driving me nuts. I want an automated email to be sent the 3rd business day before the end of the month.
Solved! Go to Solution.
There are really a number of parts to your question. First, you need to find the end of the current month.
Once you find the end of the month, you can use addDays() and subtract 2 more days from it.
Then you need to know if the resulting date is a weekday.
Use a dayOfWeek() expression - that will return Sunday as 0 and Saturday as 6.
You can use a condition or write an expression that says if the day of week is 0 or 6, subtract two days from the date (use an addDays() expression).
If you need an example, let me know.
I notice @ScottShearer has given you an idea, I was working on the solution and will go ahead and post my version as follows.
First, using the "Add to Time" action, I can get the start of this month and add 1 month to the date i.e. with today being 09/11/2021 (it the UK at least 😅), this would return 01/12/2021. Then using the same action again, I am able to subtract a day and get the end of this month i.e. 30/11/2021.
Next I have created an array of dates (using a select on a range 0 to 7, the last 7 days of this month and used an expression to indicate the day of the week, 0 and 6 being Sunday and Saturday. I use sub to turn the item() into a negative, i.e. Sub(0,0) is 0, sub(0,1) is -1, then -2 etc. This allows me to get the last 7 days of the month, including the last day of the month. I probably on need the last 5 but this will allow you or someone else to adapt for 4th last day, 5th last day etc.
Filter Array (in advanace mode)
@and(not(equals(item()?['dayofweek'], 0)),not(equals(item()?['dayofweek'], 6)))
The final compose is to return the 3rd element of the array (after it has been filtered). Elements start from 0,1,2 and so the 3rd element is called by integer 2.
Hopefully this helps you to achieve your goal, pretty complicated but a good challenge.
Please consider accepting my answer as a solution if it helps to solve your problem.
Please take a look and subscribe to my YouTube Channel for more Power Platform ideas and concepts, or take a look at my website. Thanks
To find the day three days before the month ends, add a condition and compare
The first expression just cuts the hours, minutes and seconds off the timestamp, so you get the plain date.
The second adds a month to the timestamp which will move you into the following month (don't worry, if you add a month to the 1st of January, you will get the 28th of February, not the 2nd of March), then goes to the start of this following month and subtracts three days, which brings you back three days into the current month from the end of it.
If both render the same result, you know you are three days before the current month ends.
@DamoBird365 Thanks a ton for the solution! As a newbie it took me a while to follow but I got it to work! 🙂
Would you mind finishing it off and letting me know how I loop it in with actually sending the email? I am familiar with the email composure piece but how do I get to to shoot off the email on that specific date? Is it as simple as adding "Send email with options"?
I would setup a daily recurrence trigger, and then implement a condition. If utcnow() equals 3rd business day of month, branch yes, else branch no. You might need to use formatdatetime() to ensure both dates are in same format. I.e. formatdatetime(date,'yyyy-MM-dd').
I guess the other option would be to set up a recurrence based on 22nd of each month and then use the delay action based on the new date. Your flow would wait until that date and wouldn't therefore run daily.
to achieve a mail being sent off three workdays before the end of a month, you'd have to do several things. Parts are already described above.
Can you maybe be more specific regarding the latter issue? Holidays or not?
I thought about the "business" day question a little longer. As long as we can ignore holidays, a formula calculating the third-last business day of the current month is:
The condition is
startOfDay(utcNow()) eq subtractFromTime(startOfMonth(addToTime(utcNow(),1,'Month')),min(4,max(2,mod(add(3,dayOfWeek(utcNow())),7))),'Day')
I like that you have used expressions and a single action but I am not getting the 3rd last business day of the month.
Can you explain your thinking as it is definitely much cleaner than mine 😉
I shall try 🙂
Should be easily fixed - I just don't have the time to test it right now. I assume shifting min, max and add up one each will do the trick.
The first Microsoft-sponsored Power Platform Conference is coming in September. 100+ speakers, 150+ sessions, and what's new and next for Power Platform.
Join us on June 28 for our monthly User Group leader call!
Learn to digitize and optimize business processes and connect all your applications to share data in real time.
Are you new to designing flows? What is your biggest struggle with Power Automate Designer? Help us make it more user friendly!