decimal place

[sfoerst]

Is it possible to limit a float to 2 decimal place?

[gamoraes · Accepted solution]

Hi @sfoerst

Limit the float variable no, but you can use an action to transform cutting the others decimals places.

The expression to do this is :

if the float value is in a variable : 

substring(string(variables('VARIABLE_NAME')),0,add(indexof(string(variables('VARIABLE_NAME')),'.'),3))

also, if is in a action:

substring(actionOutputs('ACTION_NAME'),0,add(indexof(actionOutputs('ACTION_NAME'),'.'),3))

In this fuction the 3 is the count of decimal places plus the dot place.

If you need more help, post here.

Hope Have Helped,

Gustavo Moraes

[sfoerst]

Where do i have to put in that code snipped?

I have a variable as a string. 

Thanks

[gamoraes]

Hi @sfoerst, i recommend you to use a 'Compose' action.

Look the images:

How i did

 After yoiu can use this compose to do your flow.

Result

 Hope Have Helped,

Gustavo Moraes

[sfoerst]

almost

[sfoerst]

substring(string(variables('4.68750000000000')),0,add(indexof(string(variables('4.68750000000000')),'.'),3))sub

[gamoraes · Accepted solution]

Hi @sfoerst you need to click inside dynamic content to use expression and put that function inside the red square,

like the print below:

 OBS: I see the text inside variable is the float value, in the snippet that i post you need to put the Variable Action name, if you have direct value, can remove the literal text "variable"

Best Regards,

Gustvo Moraes

[sfoerst]

Thank you it works!!!

[BG22]

@gamoraes You are my hero and if you were present I would buy you lunch! THANK YOU!!

[PatUmaknow]

Hi,

To overcome the problem of having a decimal number with only one decimal, simply add an insignificant number to it, like 0,00001. 

This way you automatically always have more that 2 decimals.

Here is the formula:

substring(string(add(triggerBody()['number'],0.000001)),0,add(indexof(string(add(triggerBody()['number'],0.000001)),'.'),3))

[LEARN_IT]

This method does not work if You run numbers like. 390.00 or 290.00. I'm getting results 39 ir 29

Here is my formula: 

substring(string(variables('TotalExpense')),0,add(indexof(string(variables('TotalExpense')),'.'),3))

[gamoraes]

Hi @LEARN_IT, the problem with your expression is in red, you need to put the length of decimal places(in your case 2)

substring(string(outputs('Compose')),0,add(indexof(string(outputs('Compose')),'.'),3))

The correct function to remove decimal with 2 places are

substring(string(outputs('Compose')),0,add(indexof(string(outputs('Compose')),'.'),2))

[Murderbot]

One note here, it may be wise to convert it back into a float by adding float() as the last step of the formula.

float(substring(string(outputs('Get_Running_Total')),0,add(indexof(string(outputs('Get_Running_Total')),'.'),3)))

[degvalentine]

I posted a solution that rounds a float to hundreths on another thread. The solutions above truncate.

[nmccool]

the decimal solution worked for me, BUT do you also have a solution for adding the comma in appropriate places?

[degvalentine]

Yup. See my post here. My 2nd post on that thread has the more robust, expanded version.