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Helper III

## Add on working days to Today()

I am trying to, on the push of a button, set a date which is Today() + X number of working days. I cannot figure out how to get this working to account for every eventuality. I am going to be creating a number of tasks (list items) at one time using Patch and all of them will have a different Due Date (Today() + X days).

Thanks

1 ACCEPTED SOLUTION

Accepted Solutions
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Super User III

## Re: Add on working days to Today()

In the OnSelect property your button, you can add the following code:

``````Set(varDaysToAdd,3);
Set(varResult, DateAdd(Today(),
Value(varDaysToAdd) +
RoundDown(Value(varDaysToAdd) / 5, 0)*2+
Switch(Weekday(Today()),5,If(Mod( Value(varDaysToAdd) , 5)>0,2,0),
4,If(Mod( Value(varDaysToAdd) , 5)>1,2,0),
3,If(Mod( Value(varDaysToAdd) , 5)>2,2,0),
2,If(Mod( Value(varDaysToAdd) , 5)>3,2,0),
1,If(Mod( Value(varDaysToAdd) , 5)>4,2,0))
)
)``````

The variable varDays defines the number of days to add (3 in this example).
The set statement stores the result of the calculation in the variable varResult.

This formula is based on @Siennas logic to exclude to exclude Saturdays & Sundays, so the credit goes to him.

2 REPLIES 2
Highlighted
Responsive Resident

## Re: Add on working days to Today()

Hi @sammybridge,

It may be that the DateAdd() function could work for you. The syntax is DateAdd(date, number_of_units, unit)

So in your instance, if you can pre-determine somewhere in your app for the amount of days to add for each list item, you can simply use DateAdd(Today(), number_of_days, Days), where number_of_days refers to the value assigned to this list item.

Highlighted
Super User III

## Re: Add on working days to Today()

In the OnSelect property your button, you can add the following code:

``````Set(varDaysToAdd,3);
Set(varResult, DateAdd(Today(),
Value(varDaysToAdd) +
RoundDown(Value(varDaysToAdd) / 5, 0)*2+
Switch(Weekday(Today()),5,If(Mod( Value(varDaysToAdd) , 5)>0,2,0),
4,If(Mod( Value(varDaysToAdd) , 5)>1,2,0),
3,If(Mod( Value(varDaysToAdd) , 5)>2,2,0),
2,If(Mod( Value(varDaysToAdd) , 5)>3,2,0),
1,If(Mod( Value(varDaysToAdd) , 5)>4,2,0))
)
)``````

The variable varDays defines the number of days to add (3 in this example).
The set statement stores the result of the calculation in the variable varResult.

This formula is based on @Siennas logic to exclude to exclude Saturdays & Sundays, so the credit goes to him.

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