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Tom_Slosse
Memorable Member
Memorable Member

Auto Increment Id in a Collection, and update collection via that Id.

Hey all

 

 

Before I start of things, I already made this work with a SQL table, but now I want to recreate this but with a collection, to have faster loadings and just to test it out in general.

 

But Im struggling with the following, I want to add tasks to a collection with a Id that auto increments everytime a new task is created.

What also needs to possible is that a task can be modified and can be deleted.

 

Now the incrementing Id works fine only passing that Id to a new task doenst seem to work.

 

I hope the screenshots below make it a bit more cleat what I try to achieve.

 

Kind regards

 

 

Tom

 

New Task screenNew Task screen

FIrst task saved in the collection, makes a blank record with itFIrst task saved in the collection, makes a blank record with itTasklist viewTasklist view

 

 

 

 

OnHidden NewTaskOnHidden NewTask

 

 

 

 

OnVisible of the NewTask ScreenOnVisible of the NewTask ScreenUpdatecontext IdUpdatecontext IdUpdated IdUpdated IdTaskCollection, where only two tasks can be added apparentlyTaskCollection, where only two tasks can be added apparentlyI

 

 

 



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2 REPLIES 2
v-monli-msft
Community Support
Community Support

Hi @Tom_Slosse,

 

Would you please shared the formula you used to create the collection? 

 

Regards,

Mona

Community Support Team _ Mona Li
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

Hey @v-monli-msft

 

 

I solved my problem by adding some more screens to my app. So I have one for a New Task and one for Edit Task now and it works fine. I guess the auto increment Id wasn't the problem but the resetting of the field won't work and I think that messed it up. 

 

But thanks for the reply.

 

Kind regards

 

 

Tom



If this reply has answered your question or solved your issue, please mark this question as answered.

Answered questions helps users in the future who may have the same issue or question quickly find a resolution via search. If you liked my response, please consider giving it a thumbs up.

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