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Frequent Visitor

Bing map zoom

Someone having an working (Bing) link for getting zoom to work on the map.

 

Followed this quide but can`t get zoom to work.

 

https://powerapps.microsoft.com/en-us/blog/image-control-static-maps-api/

 

Having troble getting this link to work

 

"https://dev.virtualearth.net/REST/V1/Imagery/Map/"&drpBingImagerySets.Selected.Value&"/" & EncodeUrl(txtLocation.Text) & "/"& slZoom.Value &"?mapSize=" & txtImageWidth & "," & txtImageHeight & "&pp=" & txtLocation.Text & ";21;I+am+here&key="&txtBingMapsKey.Text

 

 

 

 

1 ACCEPTED SOLUTION

Accepted Solutions

Hi @Leinad

 

Supposing that txtLocation contains your location in a coma separated format like this:

 

51.51128434,-0.1191578

 

You can use this formula:

 

 

"http://dev.virtualearth.net/REST/v1/Imagery/Map/Road/" &
txtLocation.Text  & 
"/13?mapSize=500,500&key=<YourKey>"

 

As stated in the article you mention, you can set the default property of txtLocation to the following formula in order to retrieve the location on a 'location aware' device.

 

Location.Latitude & "," & Location.Longitude

 

View solution in original post

3 REPLIES 3
Super User III
Super User III

Hi @Leinad

 

Here's a link that works for me. The part that's highlighted controls the zoom level. I believe that this can be a number up to 21.

 

http://dev.virtualearth.net/REST/v1/Imagery/Map/Road/51.51128434,-0.11915781/13?mapSize=500,500&key=<YourKey>

Hope that's of some help.

Frequent Visitor

Hej Timl

Yes that like is working, but is has the GPS coordinate it the link, what I want to use txtLocation so it can be different coordinate depending on txtLocation value, which is working fine as long I don't add any zoom value.

Hi @Leinad

 

Supposing that txtLocation contains your location in a coma separated format like this:

 

51.51128434,-0.1191578

 

You can use this formula:

 

 

"http://dev.virtualearth.net/REST/v1/Imagery/Map/Road/" &
txtLocation.Text  & 
"/13?mapSize=500,500&key=<YourKey>"

 

As stated in the article you mention, you can set the default property of txtLocation to the following formula in order to retrieve the location on a 'location aware' device.

 

Location.Latitude & "," & Location.Longitude

 

View solution in original post

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