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Caleb62881177
Post Prodigy
Post Prodigy

Count Concatenated DisplayNames in SharePoint

Good Day Everyone,

 

I got a SharePoint list that has a column with DisplayNames Concatenated to together.

I would like to see if the current user of the app DisplayName is in that column and Countrow the DisplayName if possible.

 

Example:

Column1

DisplayName1;DisplayName2;DisplayName3;DisplayName4 

 

Please help me.

8 ACCEPTED SOLUTIONS

Accepted Solutions
Amik
Super User
Super User

@Caleb62881177 - I am assuming your DisplayNames column is a multi-select People Picker column in SharePoint? Or is it actually Single Line Text?

 

For a People Picker, you can apply the following to a Label to check if the current logged in user exists in that column:

 

With(
    {
        _data: Filter(
            Ungroup(
                ForAll(
                    'Your SharePoint List',
                    Split(
                        Concat(
                            'Your People Column',
                            DisplayName & ";"
                        ),
                        ";"
                    )
                ),
                "Value"
            ),
            Value = Office365Users.MyProfileV2().displayName
        )
    },
    CountRows(_data) > 0
)

 

To count the number of instances the logged user appears in that column, simply remove "> 0 " from the above expression:

 

With(
    {
        _data: Filter(
            Ungroup(
                ForAll(
                    'Your SharePoint List',
                    Split(
                        Concat(
                            'Your People Column',
                            DisplayName & ";"
                        ),
                        ";"
                    )
                ),
                "Value"
            ),
            Value = Office365Users.MyProfileV2().displayName
        )
    },
    CountRows(_data)
)

 

For a Single Line Text Column, a similar principle would apply, except you do not need the Concat function:

 

With(
    {
        _data: Filter(
            Ungroup(
                ForAll(
                    'Your SharePoint List',
                    Split(
                        DisplayName,
                        ";"
                    )
                ),
                "Value"
            ),
            Value = Office365Users.MyProfileV2().displayName
        )
    },
    CountRows(_data)
)

 

 

Notes:

  • You will need to add the Office365Users connector into your app to run any of the above expressions.

 


------------------------------------------------------------------------------------------------------------------------------


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Imran-Ami Khan

View solution in original post

Amik
Super User
Super User

@Caleb62881177 - same principle, use another With function to return a count from the Full Report table, and then sum both results:

 

With(
    {
        _data: Filter(
            Ungroup(
                ForAll(
                    'Your SharePoint List',
                    Split(
                        DisplayName,
                        ";"
                    )
                ),
                "Value"
            ),
            Value = Office365Users.MyProfileV2().displayName
        )
    },
    With(
        {
            _fullreport: Filter(
                Ungroup(
                    ForAll(
                        'Full Report',
                        Split(
                            Nominee,
                            ";"
                        )
                    ),
                    "Value"
                ),
                Value = Office365Users.MyProfileV2().displayName
            )
        },
        Sum(
            CountRows(_data),
            CountRows(_fullreport)
        )
    )
)

 

 


------------------------------------------------------------------------------------------------------------------------------


If I have answered your question, please mark your post as Solved. Remember, you can accept more than one post as a solution.

If you like my response, please give it a Thumbs Up.

Imran-Ami Khan

View solution in original post

Amik
Super User
Super User

@Caleb62881177 - if Full Report table does not contain concatenated Display Names, then the second solution I provided was wrong - the use of the For All and the Concat function would have been pointless because they were only relevant for concatenated fields with a delimiter. 

 

Anyway, in answer to your third question, use:

 

With(
    {
        _data: Filter(
            Ungroup(
                ForAll(
                    'Your SharePoint List',
                    Split(
                        DisplayName,
                        ";"
                    )
                ),
                "Value"
            ),
            Value = Office365Users.MyProfileV2().displayName
        )
    },

    With(
        {
            _fullreport: Filter(
                ForAll(
                    Distinct(
                        'Full Report',
                        ThisRecord

                    ),
                    Value
                ),
                Nominee = Office365Users.MyProfileV2().displayName
            )
        },
        Sum(
            CountRows(_data),
            CountRows(_fullreport)
        )
    )
)
//The ThisRecord property allows an entire record rather than an individual field. This can be used to remove duplicate rows with one line of code.

 

 

 

 


------------------------------------------------------------------------------------------------------------------------------


If I have answered your question, please mark your post as Solved. Remember, you can accept more than one post as a solution.

If you like my response, please give it a Thumbs Up.

Imran-Ami Khan

View solution in original post

Amik
Super User
Super User

@Caleb62881177 to do this, you're going to need an index or integer column in your SharePoint list, then run a sort against that index to uniquely identify the previous row. 

 

Although there is an Index function in Power Apps, this function is not designed to automatically index a table. So if you do not already have an index, you can run the following workaround with a Collection.

 

Consider the example below:

 

ClearCollect(
    MyExampleTable,
    {TextColumn: "Text1", DateColumn: Date(2019,1,1), ColumnIndex: 0},
    {TextColumn: "Text1", DateColumn: Date(2019,1,1), ColumnIndex: 0},
    {TextColumn: "Text2", DateColumn: Date(2020,1,1), ColumnIndex: 0},
    {TextColumn: "Text2", DateColumn: Date(2020,1,1), ColumnIndex: 0},
    {TextColumn: "Text3", DateColumn: Date(2021,1,1), ColumnIndex: 0},
    {TextColumn: "Text4", DateColumn: Date(2022,1,1), ColumnIndex: 0},
    {TextColumn: "Text5", DateColumn: Date(2023,1,1), ColumnIndex: 0}
);
ClearCollect(
    IndexedCollection,
    ForAll(
        Sequence(CountRows(MyExampleTable)),
        Patch(
            MyExampleTable,
            Last(
                FirstN(
                    MyExampleTable,
                    Value
                )
            ),
            {ColumnIndex: Value}
        )
    )
)

 

Unfortunately, as far as I am aware it is not possible to compare a record with another record, so you will need to go the long way and compare each column in the current record with each column in the previous record to confirm if both records are the same.

 

For example, apply the below to a Label. This expression will evaluate whether all columns in the current row match all columns in the previous row, then Filter the output where the TextColumn = "Text1", and then finally wrap the result with a CountRows function to get the number of rows.

 

CountRows(
    Filter(
        AddColumns(
            AddColumns(
                MyExampleTable,
                "_record_previous",
                ColumnIndex - 1
            ),
            "_record_equals_previous",
            LookUp(
                MyExampleTable,
                ColumnIndex = _record_previous,
                TextColumn
            ) = ThisRecord.TextColumn && LookUp(
                MyExampleTable,
                ColumnIndex = _record_previous,
                DateColumn
            ) = ThisRecord.DateColumn
        ),
        !Boolean(_record_equals_previous) && TextColumn = "Text1"
    )
)

 

 

 


------------------------------------------------------------------------------------------------------------------------------


If I have answered your question, please mark your post as Solved. Remember, you can accept more than one post as a solution.

If you like my response, please give it a Thumbs Up.

Imran-Ami Khan

View solution in original post

Amik
Super User
Super User

@Caleb62881177 - yes, as mentioned in my earlier post you're likely going to need to handle that error with an IfError function if those Display Names do not exist in Office 365 Users.

 

See below:

 

Concat(
    AddColumns(
        AddColumns(
            Filter(
                RenameColumns(//split returns a single table column called "Value". optionally renamed the column to understand what is going on
                    Split(
                        Concat(
                            myDisplayNames,
                            Nominee & ";"
                        ),
                        ";"
                    ),
                    "Value",
                    "DisplayName"
                ),
                DisplayName <> ""
            ),
            "_get_email",
            First(Office365Users.SearchUser({searchTerm: DisplayName})).Mail//use the SearchUser action to get the Mail attribute
        ),
        "_department",
        IfError( //handle if the user does not exist
            Office365Users.UserProfile(_get_email).Department,
            ""
        )
    ),
    _department,
    ";"
)

 

DropColumns(
    AddColumns(
        GroupBy(
            DropColumns(
                AddColumns(
                    AddColumns(
                        Filter(
                            RenameColumns(//split returns a single table column called "Value". optionally renamed the column to understand what is going on
                                Split(
                                    Concat(
                                        myDisplayNames,
                                        Nominee & ";"
                                    ),
                                    ";"
                                ),
                                "Value",
                                "DisplayName"
                            ),
                            DisplayName <> ""
                        ),
                        "_get_email",
                        First(Office365Users.SearchUser({searchTerm: DisplayName})).Mail//use the SearchUser action to get the Mail attribute
                    ),
                    "_department",
                    IfError(//handle if the user does not exist
                        Office365Users.UserProfile(_get_email).Department,
                        ""
                    )
                ),
                "_get_email"
            ),
            "DisplayName",
            "GroupedItems"
        ),
        "Departments",
        Concat(
            GroupedItems,
            _department,
            ";"
        )
    ),
    "GroupedItems"
)

 

 


------------------------------------------------------------------------------------------------------------------------------


If I have answered your question, please mark your post as Solved. Remember, you can accept more than one post as a solution.

If you like my response, please give it a Thumbs Up.

Imran-Ami Khan

View solution in original post

Amik
Super User
Super User

@Caleb62881177 thanks that is much clearer. Try wrapping the Split function with Trim:

 

With(
    {
        _data: Filter(
            Ungroup(
                ForAll(
                    myDisplayNames,
                    Trim(
                        Split(
                            Nominee,
                            ";"
                        )
                    )
                ),
                "Value"
            ),
            Value = "DisplayName1"
        )
    },
    CountRows(_data)
)

 

 

 


------------------------------------------------------------------------------------------------------------------------------


If I have answered your question, please mark your post as Solved. Remember, you can accept more than one post as a solution.

If you like my response, please give it a Thumbs Up.

Imran-Ami Khan

View solution in original post

Amik
Super User
Super User

@Caleb62881177 - you mean if Today's date is greater than or equal to Date Picker 1, but is less than or equal to Date Picker 2, disable the Button?


Apply the below to the DisplayMode property of the Button

If(
    Today() >= DatePicker1.SelectedDate && Today() <= DatePicker2.SelectedDate,
    DisplayMode.Disabled,
    DisplayMode.Edit
) 

 

 


------------------------------------------------------------------------------------------------------------------------------


If I have answered your question, please mark your post as Solved. Remember, you can accept more than one post as a solution.

If you like my response, please give it a Thumbs Up.

Imran-Ami Khan

View solution in original post

Amik
Super User
Super User

@Caleb62881177 - I am not quite understanding your expressions and what purpose they serve.

 

But if we focus on removing records where "the Nominee, Nominator and Category that has the same value", then GroupBy would be most applicable here.

 

Suppose we have the following Collection:

 

ClearCollect(MySampleData, 
            {Nominee: "DisplayNameX", Nominator: "DisplayNameX", Category: "CategoryX", Jude: "JudgeName1"},
            {Nominee: "DisplayNameX", Nominator: "DisplayNameX", Category: "CategoryX", Jude: "JudgeName2"},
            {Nominee: "DisplayName1", Nominator: "DisplayName2", Category: "Category1", Jude: "JudgeName1"},
            {Nominee: "DisplayName1", Nominator: "DisplayName2", Category: "Category1", Jude: "JudgeName2"},
            {Nominee: "DisplayName3", Nominator: "DisplayName1", Category: "Category2", Jude: "JudgeName2"},
            {Nominee: "DisplayName2", Nominator: "DisplayName2", Category: "Category3", Jude: "JudgeName2"},
            {Nominee: "DisplayName1", Nominator: "DisplayName3", Category: "Category2", Jude: "JudgeName3"}
            )

 

All rows in this collection are unique. If we want to remove rows where the first three columns (Nominee, Nominator and Category are the same), we can use:

 

ClearCollect(
    MyCollection,
    DropColumns(
        AddColumns(
            GroupBy(
                MySampleData,
                "Nominee",
                "Nominator",
                "Category",
                "GroupedItems"
            ) As temp,
            "Jude",
            LookUp(
                MySampleData,
                Nominee = temp.Nominee,
                Jude
            )
        ),
        "GroupedItems"
    )
)

 

 


------------------------------------------------------------------------------------------------------------------------------


If I have answered your question, please mark your post as Solved. Remember, you can accept more than one post as a solution.

If you like my response, please give it a Thumbs Up.

Imran-Ami Khan

View solution in original post

60 REPLIES 60
Amik
Super User
Super User

@Caleb62881177 - I am assuming your DisplayNames column is a multi-select People Picker column in SharePoint? Or is it actually Single Line Text?

 

For a People Picker, you can apply the following to a Label to check if the current logged in user exists in that column:

 

With(
    {
        _data: Filter(
            Ungroup(
                ForAll(
                    'Your SharePoint List',
                    Split(
                        Concat(
                            'Your People Column',
                            DisplayName & ";"
                        ),
                        ";"
                    )
                ),
                "Value"
            ),
            Value = Office365Users.MyProfileV2().displayName
        )
    },
    CountRows(_data) > 0
)

 

To count the number of instances the logged user appears in that column, simply remove "> 0 " from the above expression:

 

With(
    {
        _data: Filter(
            Ungroup(
                ForAll(
                    'Your SharePoint List',
                    Split(
                        Concat(
                            'Your People Column',
                            DisplayName & ";"
                        ),
                        ";"
                    )
                ),
                "Value"
            ),
            Value = Office365Users.MyProfileV2().displayName
        )
    },
    CountRows(_data)
)

 

For a Single Line Text Column, a similar principle would apply, except you do not need the Concat function:

 

With(
    {
        _data: Filter(
            Ungroup(
                ForAll(
                    'Your SharePoint List',
                    Split(
                        DisplayName,
                        ";"
                    )
                ),
                "Value"
            ),
            Value = Office365Users.MyProfileV2().displayName
        )
    },
    CountRows(_data)
)

 

 

Notes:

  • You will need to add the Office365Users connector into your app to run any of the above expressions.

 


------------------------------------------------------------------------------------------------------------------------------


If I have answered your question, please mark your post as Solved. Remember, you can accept more than one post as a solution.

If you like my response, please give it a Thumbs Up.

Imran-Ami Khan

SpongYe
Super User
Super User

Hi @Caleb62881177 

 

I achieved this by doing:

CountRows(MatchAll(Concat(colTestNames, Column1, ";"), "DisplayName1"))

SpongYe_0-1695292147375.png


-----------------------
PowerYsa Power Platform Enthusiast [LinkedIn] | [Youtube]

I love to share my knowledge and learn from others. If you find my posts helpful, please give them a thumbs up 👍 or mark them as a solution ✔️. You can also check out my [@PowerYSA] for some cool solutions and insights. Feel free to connect with me on any of the platforms above. Cheers! 🍻

 

Caleb62881177
Post Prodigy
Post Prodigy

It's a Single Line Text column.

SpongYe
Super User
Super User

Hi @Caleb62881177 

 

Try this:

 

CountRows(Filter(Split(Label1.Text, ";"), Value = "DisplayName1"))

 

 

-----------------------
PowerYsa Power Platform Enthusiast [LinkedIn] | [Youtube]

I love to share my knowledge and learn from others. If you find my posts helpful, please give them a thumbs up 👍 or mark them as a solution ✔️. You can also check out my [@PowerYSA] for some cool solutions and insights. Feel free to connect with me on any of the platforms above. Cheers! 🍻

@Caleb62881177 - there is a solution for Single Line Text in my response.

 

 


------------------------------------------------------------------------------------------------------------------------------


If I have answered your question, please mark your post as Solved. Remember, you can accept more than one post as a solution.

If you like my response, please give it a Thumbs Up.

Imran-Ami Khan

Caleb62881177
Post Prodigy
Post Prodigy

@Amik , Thank you for you help. The formula worked for The Single Line.

Can you help me modify the formula below to check two different SP List for a DisplayName and Return a numeric value instead of True or False value?

 

errorr5.jpg

Amik
Super User
Super User

@Caleb62881177 please remember to accept the Solution for the first question.

 

I have a couple of questions on your second requirement:

 

  1. What is the field type for Nominee? Is it also Single Line Text?
  2. Is the 'Full Report' table also a SharePoint List?
  3. Do you want to SUM to the count of display names in both lists?

 


------------------------------------------------------------------------------------------------------------------------------


If I have answered your question, please mark your post as Solved. Remember, you can accept more than one post as a solution.

If you like my response, please give it a Thumbs Up.

Imran-Ami Khan

Amik
Super User
Super User

@Caleb62881177 please remember to accept the Solution for the first question.

 

I have a couple of questions on your second requirement:

 

  1. What is the field type for Nominee? Is it also Single Line Text?
  2. Is the 'Full Report' table also a SharePoint List?
  3. Do you want to SUM to the count of display names in both lists?

 


------------------------------------------------------------------------------------------------------------------------------


If I have answered your question, please mark your post as Solved. Remember, you can accept more than one post as a solution.

If you like my response, please give it a Thumbs Up.

Imran-Ami Khan

Caleb62881177
Post Prodigy
Post Prodigy

Hi @Amik ,

 

Sorry for responding now.

 

Nominee is a Single Line Text.

Full Report is a SharePoint List.

I want to check if that Display is present in Countrows  or with the formula you provided and add that up.

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The 2024 Microsoft 365 Conference is one of the world’s largest gatherings of Microsoft engineers and community, with a strong focus on Power Platform, SharePoint, Azure, and the transition to an AI-powered modern workplace.   Click the image link below to find out more and be prepared to be enlightened, educated, and inspired at #M365Conf24!   LATEST COMMUNITY BLOG ARTICLES Power Apps Community Blog Power Automate Community Blog Copilot Studio Community Blog Power Pages Community Blog Check out 'Using the Community' for more helpful tips and information: Power Apps, Power Automate, Copilot Studio, Power Pages  

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If you were one of the thousands of people who joined us at the first #MPPC Microsoft Power Platform Conference in 2022 in Orlando--or attended the second-annual conference in Las Vegas in 2023--we are excited to honor you with a special community badge! Show your support for #MPPC Microsoft Power Platform Conference this year by claiming your badge!         Just follow this link to claim your badge for attending #MPPC in 2022 and/or 2023: MPPCBadgeRequest    Want to earn your badge for 2024? Just keep watching our News & Announcements for the latest updates on #MPPC24.

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