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Caleb62881177
Post Prodigy
Post Prodigy

Count Concatenated DisplayNames in SharePoint

Good Day Everyone,

 

I got a SharePoint list that has a column with DisplayNames Concatenated to together.

I would like to see if the current user of the app DisplayName is in that column and Countrow the DisplayName if possible.

 

Example:

Column1

DisplayName1;DisplayName2;DisplayName3;DisplayName4 

 

Please help me.

60 REPLIES 60

@Amik You welcome.

 

Full Report SP List doesn't have any concatenated values, but it will have duplicate records.

This particular question is related to the previous one, it just that I don't want to include the duplicated records to the overall sum/count.

Amik
Super User
Super User

@Caleb62881177 - if Full Report table does not contain concatenated Display Names, then the second solution I provided was wrong - the use of the For All and the Concat function would have been pointless because they were only relevant for concatenated fields with a delimiter. 

 

Anyway, in answer to your third question, use:

 

With(
    {
        _data: Filter(
            Ungroup(
                ForAll(
                    'Your SharePoint List',
                    Split(
                        DisplayName,
                        ";"
                    )
                ),
                "Value"
            ),
            Value = Office365Users.MyProfileV2().displayName
        )
    },

    With(
        {
            _fullreport: Filter(
                ForAll(
                    Distinct(
                        'Full Report',
                        ThisRecord

                    ),
                    Value
                ),
                Nominee = Office365Users.MyProfileV2().displayName
            )
        },
        Sum(
            CountRows(_data),
            CountRows(_fullreport)
        )
    )
)
//The ThisRecord property allows an entire record rather than an individual field. This can be used to remove duplicate rows with one line of code.

 

 

 

 


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Imran-Ami Khan

Hi @Amik ,

 

Your second solution wasn't wrong, I just wanted to add more functionality on that second solution with the exclusion of other columns.

Caleb62881177
Post Prodigy
Post Prodigy

@Amik I have another question that is kind of similar to the previous one.

 

I want to count only on the Full Report SharePoint List, using the Nominator(Single Line Text) column to/sum and where the formula doesn't count a record that has the same columns with the exact value that was in a previous record.

Full Report doesn't contain any concatenated values. The solution should only give me a count of 1 instead of 3.

 

 

nominator.jpg

Amik
Super User
Super User

@Caleb62881177 to do this, you're going to need an index or integer column in your SharePoint list, then run a sort against that index to uniquely identify the previous row. 

 

Although there is an Index function in Power Apps, this function is not designed to automatically index a table. So if you do not already have an index, you can run the following workaround with a Collection.

 

Consider the example below:

 

ClearCollect(
    MyExampleTable,
    {TextColumn: "Text1", DateColumn: Date(2019,1,1), ColumnIndex: 0},
    {TextColumn: "Text1", DateColumn: Date(2019,1,1), ColumnIndex: 0},
    {TextColumn: "Text2", DateColumn: Date(2020,1,1), ColumnIndex: 0},
    {TextColumn: "Text2", DateColumn: Date(2020,1,1), ColumnIndex: 0},
    {TextColumn: "Text3", DateColumn: Date(2021,1,1), ColumnIndex: 0},
    {TextColumn: "Text4", DateColumn: Date(2022,1,1), ColumnIndex: 0},
    {TextColumn: "Text5", DateColumn: Date(2023,1,1), ColumnIndex: 0}
);
ClearCollect(
    IndexedCollection,
    ForAll(
        Sequence(CountRows(MyExampleTable)),
        Patch(
            MyExampleTable,
            Last(
                FirstN(
                    MyExampleTable,
                    Value
                )
            ),
            {ColumnIndex: Value}
        )
    )
)

 

Unfortunately, as far as I am aware it is not possible to compare a record with another record, so you will need to go the long way and compare each column in the current record with each column in the previous record to confirm if both records are the same.

 

For example, apply the below to a Label. This expression will evaluate whether all columns in the current row match all columns in the previous row, then Filter the output where the TextColumn = "Text1", and then finally wrap the result with a CountRows function to get the number of rows.

 

CountRows(
    Filter(
        AddColumns(
            AddColumns(
                MyExampleTable,
                "_record_previous",
                ColumnIndex - 1
            ),
            "_record_equals_previous",
            LookUp(
                MyExampleTable,
                ColumnIndex = _record_previous,
                TextColumn
            ) = ThisRecord.TextColumn && LookUp(
                MyExampleTable,
                ColumnIndex = _record_previous,
                DateColumn
            ) = ThisRecord.DateColumn
        ),
        !Boolean(_record_equals_previous) && TextColumn = "Text1"
    )
)

 

 

 


------------------------------------------------------------------------------------------------------------------------------


If I have answered your question, please mark your post as Solved. Remember, you can accept more than one post as a solution.

If you like my response, please give it a Thumbs Up.

Imran-Ami Khan

Caleb62881177
Post Prodigy
Post Prodigy

@Amik , Thank you for your solutions.

 

I have another situation that you can please help me with, I want to get the Office365Users Department and Manager from a concatenated DisplayNames from a SharePoint List.

 

Example:

Full Report SharePoint List

Nominee (Single Line Text)

DisplayName1;DisplayName2;DisplayName3

 

Output:

Nominee

Manager1;Manager2;Manager3

 

Example:

Full Report SharePoint List

Nominee (Single Line Text)

DisplayName1;DisplayName2;DisplayName3

 

Output:

Nominee

Department1;Department2;Department3

Amik
Super User
Super User

@Caleb62881177 - why would each Nominee have multiple Managers and Departments? I would expect one Manager and one Department per DisplayName?

 


------------------------------------------------------------------------------------------------------------------------------


If I have answered your question, please mark your post as Solved. Remember, you can accept more than one post as a solution.

If you like my response, please give it a Thumbs Up.

Imran-Ami Khan

Caleb62881177
Post Prodigy
Post Prodigy

@Amik The Nominee Column will contain concatenated DisplayNames, So I want to get Manager of that concatenated DisplayNames and Departments.

I want the output to be a concatenated Managers and concatenated Departments.

Amik
Super User
Super User

@Caleb62881177 ,

 

Only way to do that is to leverage the Office 365 Users connector. This connector is an action based data source which you can leverage to return the data you need. However, in order for this to return the correct data for each user, you will need to uniquely identify each user, either by identifying their email address or upn for each DisplayName in your column (simply using the DisplayName text is not going to work).

 

You first need to create a "virtual" column using the AddColumns function to identify the email for each DisplayName, then apply that email inside the Office365Users.UserProfile action table to return the department for each email address.

 

For example, suppose we have the following Collection:

 

ClearCollect(
    myDisplayNames,
    {Nominee: "Smith, John (ACME); Rogers, Tim (ACME)"},
    {Nominee: "Storm, Susan (ACME); Khan, Imran (BTIS)"},
    {Nominee: "Singh, Harry (BTIS); Reynolds, Adam (AMC);"}
)

 

To get the Department  for each DisplayName, we can apply the following to the Items property in a Gallery:

 

AddColumns(
    AddColumns(
        Filter(
            RenameColumns(//split returns a single table column called "Value". optionally renamed the column to understand what is going on
                Split(
                    Concat(
                        myDisplayNames,
                        Nominee & ";"
                    ),
                    ";"
                ),
                "Value",
                "DisplayName"
            ),
            DisplayName <> ""
        ),
        "_get_email",
        First(Office365Users.SearchUser({searchTerm: DisplayName})).Mail//use the SearchUser action to get the Mail attribute
    ),
    "_department",
    Office365Users.UserProfile(_get_email).Department
)

 

The same principle would apply for Manager, except you will be running it against Office365Users.ManagerV2:

 

AddColumns(
    AddColumns(
        Filter(
            RenameColumns(//split returns a single table column called "Value". optionally renamed the column to understand what is going on
                Split(
                    Concat(
                        myDisplayNames,
                        Nominee & ";"
                    ),
                    ";"
                ),
                "Value",
                "DisplayName"
            ),
            DisplayName <> ""
        ),
        "_get_email",
        First(Office365Users.SearchUser({searchTerm: DisplayName})).Mail //use the SearchUser action to get the Mail attribute
    ),
    "_manager",
    Office365Users.ManagerV2(_get_email).displayName
))

 

Optional: apply the below to the Manager Label in the Gallery in case the Manager field is Blank:

 

IfError(
    ThisItem._manager,
    ""
)

 

On a separate note, I know many of your questions are related to each other, but I recommend that you post your questions as new posts on the forum for quicker responses and for different perspectives. Otherwise happy to continue using this thread if waiting is not a concern.

 

 


------------------------------------------------------------------------------------------------------------------------------


If I have answered your question, please mark your post as Solved. Remember, you can accept more than one post as a solution.

If you like my response, please give it a Thumbs Up.

Imran-Ami Khan

@Amik  I am getting this error with the Manager and Department forumula.

 

I used the ClearCollection(myDisplayNames, {Nominee: "DisplayName; DisplayName"}, {Nominee: "DisplayName; DisplayName"}) on a button to create the collection.

 

code 1.png

I think I am missing something.

 

I have asked the department and Manager on two different threads a few days ago, but didn't get actual answer.

I have no problem waiting for a response.

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