Create a Gallery with non duplicates

[Anonymous]

Hi People.!

One question.

I have one Entity that have a lot of records. The information is the next

colum1    column2   column3

PC1          PACO        IVAN

PC2          PACO        MARTIN

PC3          IVAN         PACO

PC1          PACO        IVAN

PC2          PACO        MARTIN

I must show a gallery with all different records but colum1 without repetition.  Therefore I have 2 PC1 and 2 PC2, so I should to show one of each. 

I found the distinct functions but with this function i can show just one column. I need to show the 3 colums but not show duplicated for colum1    

thank you

[mdevaney]

@Anonymous 

Here's my take on the problem.  You could try to store the records with non-duplicate records inside a Collection 

ClearCollect(myUniqueRecords,
    DropColumns(
        AddColumns(
            Distinct(
                AddColumns(
                    your_datasource_name,
                    "CombinedColumns",Column1&";;"&Column2&";;"&Column3
                ),
                CombinedColumns
            ),
            "Column1",First(Split(Result,";;")).Result,
            "Column2",First(FirstN(Split(Result,";;"),2)).Result,
            "Column3",Last(Split(Result,";;")).Result
        ),
    "Column1"
    "Column2",
    "Column3"
    )
);

I built the solution using this example from my website.  If you're having trouble visualize the solution it might help
https://matthewdevaney.com/powerapps-collections-cookbook/unique-records-in-a-collection/

---
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[v-bofeng-msft · Accepted solution]

Hi @Anonymous :

My method is similar to @mdevaney 's , the principle is to construct a new column/table that contains the value of Column1/2/3, and then deduplication. Finally, split the column again with split function.The difference of my method is to use concatenate and forall to build new table directly.

Set the gallery's items preperty to:

ForAll(
    Distinct(
        Concatenate(
            yourdatasource.column1,"##",yourdatasource.column2,"##",yourdatasource.column3),
            Result
    ),
    {
        column1: Last(FirstN(Split(Result,"##"),1)).Result,
        column2: Last(FirstN(Split(Result,"##"),2)).Result,
        column3: Last(FirstN(Split(Result,"##"),3)).Result
    }
)

Best Regards,

Bof