Display 'Person or Group' Data Type Column in Data Table

[aebara]

Hi,

I currently have a couple SP lists that are referenced in my app.

On one data table, I have a few records being displayed based on a gallery selection.

One of those columns I want displayed is a 'Person or Group' data type.

PowerApps does not like this, and is expecting a text value. Any ideas on how I could display this information as a text data type?

I am currently using ThisItem.Supervisor as my code (doesn't work).

I used ThisItem.COLUMN.Value in other areas where I had similar issues, and that worked, but not for this specific column/data type.

Thank you!

[SanjaKan]

Hi!

Did you try thisitem.supervisor.DisplayName? Maybe that will work?

[aebara]

Hey @SanjaKan,

I tried this, but also doesn't seem to be working.

Thank you for the suggestion!

[SanjaKan]

Hey!

Does it allow you to add the Supervisor column into the data table from the source?

[aebara]

Yes, I can add the 'Supervisor' field from the source, but it still loads with an error in the 'Text' property of that column.

[SanjaKan]

Unles the Supervisor column is saved as text type in the list, I have no idea why this is happening.

Maybe disconnecting the source and re connceting it again sets everything right.

[v-yujincui-msft]

Hi @aebara ,

I agree with what @SanjaKan said, if you select the corresponding column and apply the following formula on its Text property as 

ThisItem.supervisor.DisplayName

It should work.

Note that thisitem needs initial capitalization.

Best Regards,
Charlie Choi

[aebara]

Hi Charlie, thanks for taking a look, but still getting an error in this column...

If it helps at all, I had errors in another column I fixed by using this code:

Concat(ThisItem.'Session type'.Value, Concatenate(Text(Value),", "))

[WarrenBelz]

Hi @aebara ,

I suspect your Supervisor column is multi-select, in which case if you only ever have one item selected

Concat(
   ThisItem.Supervisor,
   Value
)

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[aebara]

Hello @WarrenBelz!

Happy to see you here 😊

Still getting an error using this formula unfortunately.

Yes, this is a multi-select column. Most times there will only be one selection, but I wanted to leave the possibility of having multiple selections open.

Any more ideas?

Thank you!