cancel
Showing results for 
Search instead for 
Did you mean: 
Reply
Highlighted
Helper III
Helper III

Filter collection by values of another collection.

I have two, single column tables from two different sources that I'd like to compare and filter the first table based on whether the values are present in any record of the second table in the different source collection. Example:

Table1
----------
Value1
Value2
Value4
Value5

 

Table2
---------
Value2
Value3
Value5


I would then like Table1 to be filtered to look like

Table1
--------
Value2
Value5


I'm trying to avoid creating a new table in this scenario, which has complicated things a bit. I specifically need to filter the original table, since I'm trying to filter the default items of a combobox and it seems to be very particular about the Items table being the same source as the DefaultSelectedItems table.

1 ACCEPTED SOLUTION

Accepted Solutions
Highlighted
Dual Super User III
Dual Super User III

Hi @AdamD 

 

you can try using the below expression:
Filter(Table1,Column1 in Table2.Column2).Column1
Here Table1 is my first table and Column1 is the name of its column, Same for Table2, it has a column named Column2.
 
The result will be the values from table1 that exist in Table 2MicrosoftTeams-image (90).png

 

Hope this Helps!
 
If this reply has answered your question or solved your issue, please mark this question as answered. Answered questions helps users in the future who may have the same issue or question quickly find a resolution via search. If you liked my response, please consider giving it a thumbs up. THANKS!

View solution in original post

2 REPLIES 2
Highlighted
Dual Super User III
Dual Super User III

Hi @AdamD 

 

you can try using the below expression:
Filter(Table1,Column1 in Table2.Column2).Column1
Here Table1 is my first table and Column1 is the name of its column, Same for Table2, it has a column named Column2.
 
The result will be the values from table1 that exist in Table 2MicrosoftTeams-image (90).png

 

Hope this Helps!
 
If this reply has answered your question or solved your issue, please mark this question as answered. Answered questions helps users in the future who may have the same issue or question quickly find a resolution via search. If you liked my response, please consider giving it a thumbs up. THANKS!

View solution in original post

Highlighted

Amazing how much time I've burned away searching for that simple, elegant solution. Thank you! @yashag2255 

Helpful resources

Announcements
Community Conference

Power Platform Community Conference

Check out the on demand sessions that are available now!

News & Announcements

Community Blog

Stay up tp date on the latest blogs and activities in the community News & Announcements.

secondImage

Power Platform 2020 release wave 2 plan

Features releasing from October 2020 through March 2021

Community Highlights

Community Highlights

Check out the Power Platform Community Highlights

Top Solution Authors
Top Kudoed Authors
Users online (7,896)