Generating random serial number when sending form

[imrineeman]

Thank you

[mdevaney]

@imrineeman 

Actually, you don’t need the number to be random.  It creates the problem of having to check for duplicates.  Make a 5 digit number based off of the Item ID instead.

To do this, put my code in the OnSuccess property of your form.  It will insert the serial number for the Item after the ID is known.

Patch(your_datasource_name, LookUp(your_datasource_name, ID=Form1.LastSubmit.ID), {SerialNumber: Text(ID, “00000”})

Make sure serial number is a text type column so the leading zeros show

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[imrineeman]

I'm getting an error on this stage: Text(ID,“00000”) (expected operator, the function text has invalid arguments)

Thanks for helping

[imrineeman]

Fixed it, but it says that ID identifier isn't recognized..

[mdevaney · Accepted solution]

@imrineeman 

Try this:

Set(varPatchRecord, LookUp(your_datasource_name, ID=Form1.LastSubmit.ID));

Patch(your_datasource_name, varPatchRecord, {SerialNumber: Text(varPatchRecord.ID, “00000”)})

I changed the code and missed some brackets earlier.

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[imrineeman]

Thanks for your help.

Still same issue , on this function : Text(varPatchRecord.ID,“00000”)

[mdevaney]

@imrineeman

Are you using SharePoint as a datasource?  Can I please see a screenshot of the formula showi the error?

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[imrineeman]

Yes to sharepoint as db.

Hope this is enough

Thanks again!

[mdevaney]

@imrineeman 
You need to retype the quotation marks.  Delete them and then retype.  Its because you cut + paste my code directly from this forum and I type it on my mobile.

(Its a silly quirk of our forums).

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Please click "Accept as Solution" if my post answered your question so that others may find it more quickly. If you found this post helpful consider giving it a "Thumbs Up."

[imrineeman]

Works as a charm!

I thank you very much for your patience and help. 🙂