Global Variable is blank

[m365newuser]

Hello Everyone,

I am declaring a global variable inside a text label with the following command : Set(a, 9); 

where a is the variable name

9 is the value

However, it is not storing the value for a and is always blank.

Can someone tell me what i am doing wrong

Picture attached for reference

[eka24]

Have you click the buttom to activate the variable?

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[m365newuser]

It's a text label with an OnSelect property. (so there is nothing for me to click as such)

[eka24]

I suggest you put the formula OnSelect a button, then insert a label and put a in the text property of the Label you have inserted. What you are using is not a label, it an Icon.

You can also maintain your code on the Icon but click or select it since it has OnSelect property, it will work. But the result of 9 you expect cannot be shown on an Icon. Insert a Label and put a in the text property:

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[Abhilash_Swain]

Never tried with textbox onselect property. You can debug .use below methods.

1. Copy the codes to a button and click.if it works good, then change the onselect property .

2. If still it appears blank, check if you have used the same variable somewhere else and setting to balnk.

If it ll help give a upvote.

[m365newuser]

These are fixed values, therefore I don't want to use a button to store values. As per your picture the user would have to manually enter the values.

Also just for clarification, I am not trying to display the value of a on the icon itself. 

[m365newuser]

These are fixed values, therefore I don't want to use a button to store values. 

[Abhilash_Swain · Accepted solution]

Ok then please use them under on screen visible property. Whenever your screen will visible these data will get their values.(you can use app load property too).

[eka24]

If you dont want the user to manually click or select the button, then put the formula OnVisible of the Screen or OnStart of the App. That way, it becomes automatic.

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[TimothyTrimble]

Also keep in mind that if you put the globals in the app.OnStart, when testing, you will need to run App.OnStart.