How to fix SharePoint List Custom Form with two screens opening wrong screen second time around

[renewtx]

Hello,

I have a SharePoint list for which I created a custom form using PowerApps.  The form worked fine when I initially just had the default screen and I was able to View, Edit, and Create new items as expected.  However, I had a requirement to be able to Print my form, so I created a new (Print) Screen by inserting a Print Landscape layout screen and then added a button on my form to load the Print screen (I needed to do a separate screen/form as I needed to reformat some of the data specifically for printing).  Loading and printing appears to work fine in Preview mode.  And when I save and publish the form updates to SharePoint, when I first click on New or Edit for an item, I initially get the correct for as expected.  

However, if I click on New or Edit, for example, then click on my button to Print (which loads the Print Screen), that loads correctly as well.  But if I cancel the Print Screen, the next time I try to View, Edit, or Create New, the Print Screen is loaded instead of the standard New/Edit/View screen.  I have to refresh my browser in order to get back to the standard New/Edit/View screens after activating the Print screen.

Any idea how to fix this?  I have tried using the App OnStart() function to navigate to my standard screen, but that does not fix it (apparently OnStart(() is only loaded the first time you access the app).

Thanks

[Jeff_Thorpe · Accepted solution]

@renewtx , the OnStart only fires once when you first open an item in SharePoint in that session. When you close the custom form it is just hiding it, so when you click on another item it just becomes visible again and loads the selected item.

Try this as a workaround. Go to the SharePointIntegration control in the app and in the Advanced property add Navigate(FormScreen1, ScreenTransition.None) to the OnNew, OnEdit and OnView properties.

Out of the box example for OnNew:  

NewForm(SharePointForm1); Navigate(FormScreen1, ScreenTransition.None)