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wlt_2022
Frequent Visitor

Lookup dropdown

Hi All,

 

I currently have a page within Power Apps acting as a Check-in page. Clients check-in based on their ID using a lookup dropdown field, connected to the Clients DB.

 

When clients click on the drop down, they see all the other ID's and can search for their own (either scrolling or typing it). This then goes to a visitor log DB.

 

Is there any way for me to not show everyones IDs in the drop down? so they can just search their own.

 

Thanks!

1 ACCEPTED SOLUTION

Accepted Solutions
Amik
Super User
Super User

@wlt_2022 - If each client "knows" what their Client ID number is, I would suggest you use a Text Input control which clients can use to enter their Client ID. This removes the need for a dropdown control and the opportunity for other clients to see other Client IDs.

 

You can of course use two Text Input controls for Surname and E-mail if you wish. Whichever method you use, you can then use a Lookup function to verify if the Client exists in the Client DB.

 

Examples below using a variable which returns a boolean:

 

 

Set(
    varExists,
    !IsBlank(
        LookUp(
            clientdb,
            ClientSurname = TextInput1.Text && ClientEmail = TextInput2.Text,
            ClientID
        )
    )
)

 

 

 

Set(
    varExists,
    !IsBlank(
        LookUp(
            clientdb,
            ClientID = TextInput1.Text,
            ClientID
        )
    )
)

 

 

------------------------------------------------------------------------------------------------------------------------------

 

If I have answered your question, please mark your post as Solved. Remember, you can accept more than one post as a solution.

If you like my response, please give it a Thumbs Up.

Imran-Ami Khan

 


------------------------------------------------------------------------------------------------------------------------------


If I have answered your question, please mark your post as Solved. Remember, you can accept more than one post as a solution.

If you like my response, please give it a Thumbs Up.

Imran-Ami Khan

View solution in original post

3 REPLIES 3
Amik
Super User
Super User

@wlt_2022 - assuming each Client has a single unique ID, and you only want each Client to see their unique ID in the Dropdown, what is the purpose of using a Dropdown in the first place?

 


------------------------------------------------------------------------------------------------------------------------------


If I have answered your question, please mark your post as Solved. Remember, you can accept more than one post as a solution.

If you like my response, please give it a Thumbs Up.

Imran-Ami Khan

wlt_2022
Frequent Visitor

Thank you for your reply.

 

I don't really need to see it. Would there be an easier way for me to verify if a client exists in the 'clients' database before they are added to the 'visits' database? 

 

That way I can just have two text boxes, Surname, Email. This then verifies them against the client db and adds them to the visits db. No idea how this is done though.

 

Help would be greatly appreciated.

 

I guess the idea is to have a kiosk type system where they can do it themselves, if they are already exist in the clients DB. 

Amik
Super User
Super User

@wlt_2022 - If each client "knows" what their Client ID number is, I would suggest you use a Text Input control which clients can use to enter their Client ID. This removes the need for a dropdown control and the opportunity for other clients to see other Client IDs.

 

You can of course use two Text Input controls for Surname and E-mail if you wish. Whichever method you use, you can then use a Lookup function to verify if the Client exists in the Client DB.

 

Examples below using a variable which returns a boolean:

 

 

Set(
    varExists,
    !IsBlank(
        LookUp(
            clientdb,
            ClientSurname = TextInput1.Text && ClientEmail = TextInput2.Text,
            ClientID
        )
    )
)

 

 

 

Set(
    varExists,
    !IsBlank(
        LookUp(
            clientdb,
            ClientID = TextInput1.Text,
            ClientID
        )
    )
)

 

 

------------------------------------------------------------------------------------------------------------------------------

 

If I have answered your question, please mark your post as Solved. Remember, you can accept more than one post as a solution.

If you like my response, please give it a Thumbs Up.

Imran-Ami Khan

 


------------------------------------------------------------------------------------------------------------------------------


If I have answered your question, please mark your post as Solved. Remember, you can accept more than one post as a solution.

If you like my response, please give it a Thumbs Up.

Imran-Ami Khan

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