Referencing data from one table from a selection in another

[ChipMichael]

I have two SQL tables - '[dbo].[Person]' and '[dbo].[Department]'

In '[dbo].[Person]' there is a DepartmentID.  I want to reference the DepartmentID in '[dbo].[Department]' and return departmentName based on the selected item in '[dbo].[Person]'

I tried: 
LookUp('[dbo].[Department]', DepartmentID = '[dbo].[Person]'.Selected.DepartmentID, DepartmentName)
LookUp('[dbo].[Department]', DepartmentID = ThisItem.DepartmentID, DepartmentName)

LookUp('[dbo].[Department]', DepartmentID = DepartmentID, DepartmentName)

The third option is the only one that returns anything - and it returns the first DepartmentName in '[dbo].[Department]' for all records

[v-monli-msft]

Hi @ChipMichael,

Are you using this formula in the Items property of the Gallery control? If so, please unserstand that one Gallery could only have one data source. To use the DepartmentID from '[dbo].[Person]', you need to first insert a dropdown control, set its Items property to:

Distinct( '[dbo].[Person]',DepartmentID)

Then set the Items property of the Gallery to:

Filter('[dbo].[Department]', DepartmentID = Dropdown1.Selected.Value)

To return the DepartmentName, with the Gallery control selected, click on the table name is the right side, then pick with field you want to show in the Gallery:

Regards,

Mona

[ChipMichael]

Would it be possible to put table A in a list - reference the "selection" from that list based on a selection from table B? 

i.e., 

Table A 

PersonID   Name   DepartmentID      TitleID
     1             Jack         2                          3
     2             Jill            1                          2

Table B 

DepartmentID    DepartmentName

       1                     Marketing

       2                     Manufacturing

Table C 

TitleID          Title

  1               President
  2               Vice President
  3               Director

If I want information from PersonID 1 from Table A how do I display ?

Jack, Manufacturing, Director   

[ChipMichael · Accepted solution]

The way around this problem is to create a VIEW in SQL.  

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