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New Member

Relational filtering for drop down list

Hi All,

I am posting the data that i have and the final output that i would want but I am not able to figure out how can make dropdowns to achieve so. Any help would be appreciated.

 

This is the data that I have before

eq-idop_1op_2op_3
t-80mer = 50Mer=30mer=500
t-80pi = 60 pi=90
t-80 xyz = 90xyz=800
t-80  abc=80
t-90mer = 60Mer=30mer=500
t-90pi = 70 pi=90
t-90 xyz = 90xyz=800
t-90  abc=80

The final output should be a dropdown for the columns (op_1,op_2,op_3) which when clicked give me unique values for their corresponding ids

eq-idop_1op_2op_3
t-80Dropdown[ mer = 50,pi=60]Dropdown[ mer = 30,xyz=90]Dropdown[ mer = 500,pi=90,xyz=800,abc=80]
t-90Dropdown[ mer = 60,pi=70]Dropdown[ mer = 30,xyz=90]Dropdown[mer = 500,pi=90,xyz=800,abc=80]

 

1 ACCEPTED SOLUTION

Accepted Solutions
Highlighted
Community Support
Community Support

Hi @Prbhv ,

Do you want to transfer table1 to table2?

The point is:

1)use a gallery to display no-repeated eq-id value

2)insert 3 drop downs inside the gallery

3)make drop down1 display no-repeated op_1 value based on this item's eq-id value

4)make drop down2 display no-repeated op_2 value based on this item's eq-id value

5)make drop down3 display no-repeated op_3 value based on this item's eq-id value

 

Try to set like this:
1)insert a gallery, set its Items:

Distinct(datasorcename,eq_id)

2)set one label's Text inside the gallery:

ThisItem.Result

3)insert three drop downs inside the gallery

4)set drop down1's Items:

Distinct(
        Filter(datasourcename,eq_id=ThisItem.Result),
        op_1
)

set drop down2's Items:

 

Distinct(
        Filter(datasourcename,eq_id=ThisItem.Result),
        op_2
)

 

set drop down3's Items:

 

Distinct(
        Filter(datasourcename,eq_id=ThisItem.Result),
        op_3
)

 

If you also want to display the field name above your gallery, you just need to insert four labels above the gallery.

Set label1's text:

"eq_id"

 

Set label2's text:

 

"op_1"

 

Set label3's text:

 

"op_2"

 

Set label4's text:

 

"op_3"

 

 

 

 

Best regards,

 

Community Support Team _ Phoebe Liu
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

View solution in original post

3 REPLIES 3
Highlighted
Super User III
Super User III

so to make relationally filtered dropdowns, you will need to have some relation between the lists

 

so for example, if I have a company list and a conact list, and my contact list contains the company.

say dropdown 1 is company and dropdown2 is contact

 

If would set the items property of dropdown 2 to Filter(Contact, account=DropDown1.Selected)

Highlighted

I see but can you suggest what should be appropriate method to convert the table above to below 

Can you suggest how should i go about the coding logic for it

Highlighted
Community Support
Community Support

Hi @Prbhv ,

Do you want to transfer table1 to table2?

The point is:

1)use a gallery to display no-repeated eq-id value

2)insert 3 drop downs inside the gallery

3)make drop down1 display no-repeated op_1 value based on this item's eq-id value

4)make drop down2 display no-repeated op_2 value based on this item's eq-id value

5)make drop down3 display no-repeated op_3 value based on this item's eq-id value

 

Try to set like this:
1)insert a gallery, set its Items:

Distinct(datasorcename,eq_id)

2)set one label's Text inside the gallery:

ThisItem.Result

3)insert three drop downs inside the gallery

4)set drop down1's Items:

Distinct(
        Filter(datasourcename,eq_id=ThisItem.Result),
        op_1
)

set drop down2's Items:

 

Distinct(
        Filter(datasourcename,eq_id=ThisItem.Result),
        op_2
)

 

set drop down3's Items:

 

Distinct(
        Filter(datasourcename,eq_id=ThisItem.Result),
        op_3
)

 

If you also want to display the field name above your gallery, you just need to insert four labels above the gallery.

Set label1's text:

"eq_id"

 

Set label2's text:

 

"op_1"

 

Set label3's text:

 

"op_2"

 

Set label4's text:

 

"op_3"

 

 

 

 

Best regards,

 

Community Support Team _ Phoebe Liu
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

View solution in original post

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