Set property of component on screen

[nileshvk]

Hello,

I have built a component with the help of PowerApps Horizontal Progress Bar - YouTube

I am trying to set "ActiveStep" property using "OnSelect" function of a Icon as shown in picture below but its not working as expected. Can someone assist me with this pls?

[RandyHayes]

@nileshvk 

What is the property on the component and what is the formula on it?

[nileshvk]

Hello @RandyHayes ,

Items property of the component is:

Table({Id: 1, Label: "Asset", Visible: true},{Id: 2, Label: "Asset BreakDown1", Visible: true},
{Id: 3, Label: "Asset BreakDown2", Visible: true},{Id: 4, Label: "Asset Role", Visible: true},{Id: 5, Label: "Asset Budget", Visible: true})

I am using this component on screen to divide large input form.  I am trying to play another property "ActiveStep" of the component to change the input form. e.g. in screen shot provided earlier I want to move to a next screen i.e. "Asset Breakdown1" and so on.

[RandyHayes · Accepted solution]

@nileshvk 

My question was more about what property on the component is it that you are trying to change?

You cannot set a property of any control in PowerApps.  Your properties all have to derive their value from some place.

So if you have a ActiveStep property on the Component, then you need to set a variable and have the Component ActiveStep property derive from it.

So - Set(varActiveStep, 2)

And then your ActiveStep property on the component would be: varActiveStep

[nileshvk]

@RandyHayes , Got it. Thank you for assistance.