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BenDonahue
Continued Contributor
Continued Contributor

Setting app colors in OnStart

The Set-Up

In attempting to create a standard color palette based on out branding colors, I attempted to set these color values to variables in OnStart, so as to have easy access to them throughout the application.

 

App->OnStart, I added this code:

 

Set(_LightestYellow, ColorValue("#ffce6e"));

 

BenDonahue_0-1619012217697.png

After running OnStart, I then tried to use this in a Fill for a label, like so:

BenDonahue_1-1619012293111.png

Which filled my label with black, thusly:

BenDonahue_2-1619012341728.png

Checking my variables, I see that _LightestYellow is defined as a color, but has no value:

BenDonahue_3-1619012405671.png

Setting the Fill value for the label to the what the variable was supposed to be defined as ,

 

ColorValue("#ffce6e")

 

, fills the label with yellow:

BenDonahue_4-1619012679717.png

The Goal

I would like to have a standard block of code that I add to every app so that I can access the branding colors easily

 

The Question

What (probably super simple) thing am I missing that is preventing me from successfully defining a variable as a ColorValue()?

 

1 ACCEPTED SOLUTION

Accepted Solutions
KrishnaV
Super User III
Super User III

@BenDonahue ,


Try this,
on OnStart give only the HEX value as

Set(_LightestYellow, "#ffce6e");

 on the label fill property you say as:

ColorValue(_LightestYellow)

 This will work


I hope this resolved your issue if you see any challenge/need further help please let me know I am always happy to do it for my community.

Regards,
KrishnaV
Business Applications MVP
Twitter | Linkedin | YouTube | GitHub
If this post helps you give a and if it solved your issue consider Accept it as the solution to help the other members / new members of the community.

View solution in original post

4 REPLIES 4
KrishnaV
Super User III
Super User III

@BenDonahue ,


Try this,
on OnStart give only the HEX value as

Set(_LightestYellow, "#ffce6e");

 on the label fill property you say as:

ColorValue(_LightestYellow)

 This will work


I hope this resolved your issue if you see any challenge/need further help please let me know I am always happy to do it for my community.

Regards,
KrishnaV
Business Applications MVP
Twitter | Linkedin | YouTube | GitHub
If this post helps you give a and if it solved your issue consider Accept it as the solution to help the other members / new members of the community.

View solution in original post

BenDonahue
Continued Contributor
Continued Contributor

@KrishnaV ,

Yup, that did it. Thank you for you assistance, Krishna.

-Ben

great and happy to know. Remember when you assign the Color("djdjdj") to a variable on OnStart and then you try to use for Fill .. the variable behaves like a boolean variable and it return true or false 🙂


I hope this resolved your issue if you see any challenge/need further help please let me know I am always happy to do it for my community.

Regards,
KrishnaV
Business Applications MVP
Twitter | Linkedin | YouTube | GitHub
If this post helps you give a and if it solved your issue consider Accept it as the solution to help the other members / new members of the community.
BenDonahue
Continued Contributor
Continued Contributor

Would you go into a bit more detail on that, please?
Are you talking about this kind of code put into OnStart:
Set(_LightestBlue, ColorValue("#08c5fb"));   ?


Under what condition would it return true and under what condition would it return false?

I tried plugging

_LightestBlue

into the text field, and the error came that it was expecting a text value. Also, in the variables, it sad that _LightestBlue has no value.

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