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Frequent Visitor

pie chart question



I am quite new to this platform and I haven't managed to get a powerapp to work using other info on the board, so I hope someone could give me a step by step walk-through


I have a list (let's call it "List1")


In there I have a number of columns

Title  (not relevant for the pie chart)

Team (4 different teams)

Status (4 different project states)


I would like to generate a powerapp that create a pie graph with the # of items for each entry in "Team"


so eg:


Pie chart: status.a =5 , status.b=10 etc


Do i need to create an extra column in the sharepoint list to do these calculations or can it be done through powerapps?




Super User
Super User

Re: pie chart question

Hi @bh4 

No, it's not necessary to add a new column in your SharePoint list.

We can use the GroupBy and Count functions in PowerApps to aggregate the values. The example here is a good place to start. 

Community Support
Community Support

Re: pie chart question

Hi @bh4 ,

What he said is right @timl .

You do not need to create another column.

I suggest you use GroupBy function.

In this function, you could group your table based on team.

Try this formula:

GroupBy(List1,"Team","the same team")

And then the items that have the same team will become the same group.

You just need to display pie chart based on the group one by one.

 For example:
set the first pie chart's Items:   //display data of team1

LookUp(GroupBy(List1,"Team","the same team"),Team="Team1").the same team

set the second pie chart's Items:

LookUp(GroupBy(List1,"Team","the same team"),Team="Team2").the same team


Here's a doc about groupby function for your reference:




Best regards,

Community Support Team _ Phoebe Liu
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
Frequent Visitor

Re: pie chart question

Hi @v-yutliu-msft ,


thank you. How does the query know how to sort based on status? I cant see a status reference in the below function?


edit: the columns are "choice" type rather than plain text. could this interfere with the formula?



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