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SheltonThompson
Level: Powered On

Search/Filter to a specific record

I have two forms on a screen for different data sources. Source 1 contains a field called "ID" . Source2 contains a field called "Source1_ID" which ties the specific record back to its associated record in Source 1.

 

The form for source 1 pulls the item based on the item selected from a gallery (same source for both). I am now trying to get its associated record in Source 2 to show in the Source 2. I have tried a filter formula on the item property of the form, but its erroring out saying it returns a table instead of a specific record. How do I filter/search to a specific record for a form?

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SheltonThompson
Level: Powered On

Re: Search/Filter to a specific record

Yea that is what I tried first and it errors out stating it was expecting a record. I just added the First formula to the beginning of my filter to change the results from a table to a single record (the filter returned a single record anyways) and that worked. 

3 REPLIES 3
Super User
Super User

Re: Search/Filter to a specific record

@SheltonThompson 

 

Try this on your Item for source 2 form:

   Lookup(Source2, Source1_ID = Galleryx.Selected.ID)

 

That will lookup in the source 2 list a specific record where the Source1_ID column is equal to the ID selected in the Gallery

 

I hope this is helpful for you.

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SheltonThompson
Level: Powered On

Re: Search/Filter to a specific record

Yea that is what I tried first and it errors out stating it was expecting a record. I just added the First formula to the beginning of my filter to change the results from a table to a single record (the filter returned a single record anyways) and that worked. 

Super User
Super User

Re: Search/Filter to a specific record

@SheltonThompson 

Lookup returns single records.  Filter returns a table of matching records.

Glad you got it working.

_____________________________________________________________________________________
Digging it? - Click on the Thumbs Up. Solved your problem? - Click on Accept as Solution. Others seeking the same answers will be happy you did.

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