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yoshihirok
Memorable Member
Memorable Member

How join values in "Apply to Each" to a value after Apply to Each ?

I want to join all values in "Apply to Each" to a value after Apply to Each.

 

In my scenario:

In Apply to Each loop, create new values by Data Operations - Compose.

After the Apply to Each loop, create a value by join all values created in the loop.

This scenario can use to creating summary from some outputs from services.

 

1.png

 

 

 

 

Regards,

Yoshihiro Kawabata

 

 

1 ACCEPTED SOLUTION

Accepted Solutions

Hi @fooshen

 

Yes. Compose:"@join(outputs('Compose2'), ',')" can build a result from results in Apply to Each.

 

Regards,

Yoshihiro Kawabata

View solution in original post

9 REPLIES 9
v-micsh-msft
Community Support
Community Support

Hi @yoshihirok,

 

Could you please explain a bit regarding "Join all values" here?

Have you checked the following article?

Could the HTML Tables, or the CSVs table helps in your scenario?

Build flows with HTML Tables, CSVs and other new features link OCR and image content detection

 

Do you mean to add them all together?

 

 

Regards,

Michael

Community Support Team _ Michael Shao
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

Hi @v-micsh-msft

 

"Join all values" make from some values to a value.

Yes, the blog "Build flows with HTML Tables, ..."

 

So, I want to do same with Apply-to-each.

Step 1. Get a array value.

Step 2. Create new value in  Apply-to-each from each array items.

Step 3. Create a new value from the values in Step 2 after Apply-to-each.

 

Example scenario:

Step 1. Get a array value by Excel - Get Rows.

Step 2. Create new value in Apply-to-each from each Excel Row item

  by Data Operations - Compose, concat first column and second column.

  Example: "Col1 Col2 / Row 1"

Step 3. Create a new value from the values in Step 2 after Apply-to-each with comma seperate

  Example: "Col1 Col2 / Row 1, Col1 Col2 / Row 2, Col1, Col2 / Row 3"

 

Regards,

Yoshihiro Kawabata

Hi @yoshihirok,

 

Thanks for the update.

 

I will try some tests, and share the result later.

 

Appreciate your patience.

 

Regards,

Michael

Community Support Team _ Michael Shao
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
Anonymous
Not applicable

@v-micsh-msft

 

Has this been solved yet?

 

Is it possible to get the summary of an apply to each loop?

 

I processed an array in the loop, then I want to send all the resulting values in one email. Not each result in 1 email.

I have a similar use case.

Get a list of items from a REST API call, apply to each to perform some string manipulation and then I want to construct a string representing all the processed strings.

 

1. Compose: "@createArray('a','b','c')

2. Apply to Each: Output from 1

2.1  Compose: "concat(item(), '-1')"

3. Join: Output from 2.1, ";".

 

Step 3 throws an error saying the output from 2.1 is null.

Any suggestions?

Hi @fooshen

 

Yes. Compose:"@join(outputs('Compose2'), ',')" can build a result from results in Apply to Each.

 

Regards,

Yoshihiro Kawabata

Anonymous
Not applicable

Hi @yoshihirok

 

I am using  the technique you describe but it is outputting the formula string and not the underlying variable e.g. ["@Join(outputs('First'),'')","@Join(outputs('First'),'')","@Join(outputs('First'),'')"]

 

My formula is @Join(outputs('First'),'')

 

Any ideas what I am doing wrong? Your help would be greatly appreciated.

Lexnnn
Helper II
Helper II

I needed to send email to users only once and not repeat their email address.

This is what I have done:

if(empty(item()?['Address']),'blank',item()?['Address'])

flow contains.JPGflow contains 2.JPG

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