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lamacz
Frequent Visitor

How to receive decimal number result after dividing

hi all,

 

probably silly question, but can someone please guide me how can I receive a result in decimal number after dividing two numbers? I am always getting result in whole number. Formula looks like this:

 

div(int(variables('Recharge')),43300)
 
Thank you for any advice
Lukas
2 ACCEPTED SOLUTIONS

Accepted Solutions
ScottShearer
Super User
Super User

@lamacz:

 

How are you using the result?  Is it going into a variable?  If so, what is the data type of the variable.

 

Here is an example that shows getting a decimal output:

 

Int1.jpgInt2.jpgInt3.jpg

 

Scott

If I have answered your question, please mark your post as Solved.
If you like my response, please give it a Thumbs Up.

Scott

View solution in original post

Hi @lamacz,

 

Have your problem be solved refer to @ScottShearer 's solution?

 

As @ScottShearer 's solution, you could convert the int value to float value, then you could get the float result after div.

 

The screensho of the flow as below:

Capture.PNG

 

The expression in the Compose as below:

div(variables('Recharge'),float(43300))

The flow would run successfully as below:

Capture.PNG

 

Best regards,

Alice

 

View solution in original post

3 REPLIES 3
ScottShearer
Super User
Super User

@lamacz:

 

How are you using the result?  Is it going into a variable?  If so, what is the data type of the variable.

 

Here is an example that shows getting a decimal output:

 

Int1.jpgInt2.jpgInt3.jpg

 

Scott

If I have answered your question, please mark your post as Solved.
If you like my response, please give it a Thumbs Up.

Scott

Hi @lamacz,

 

Have your problem be solved refer to @ScottShearer 's solution?

 

As @ScottShearer 's solution, you could convert the int value to float value, then you could get the float result after div.

 

The screensho of the flow as below:

Capture.PNG

 

The expression in the Compose as below:

div(variables('Recharge'),float(43300))

The flow would run successfully as below:

Capture.PNG

 

Best regards,

Alice

 

lamacz
Frequent Visitor

hi both,

 

it was a truly silly qustion, yours solutions are working. I was incorrectly using integer type of variable to store results. 

 

Many thanks

Lukas

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