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Frequent Visitor

Increment Letter

Does anyone have a simple way to increment a letter in the alphabet to the next available letter?

A>B

B>C

and so on?

1 ACCEPTED SOLUTION

Accepted Solutions
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The idea from @RezaDorrani was more appealing to me as it obscurs the lookup list from a curious user but I could not get it to work lookup both on the ID and the Title (string). Instead I used an old fashioned approach of using a SP List with two columns

ID / Title

1 / A

2 / B

3 / C

etc.

 

Then I used the action "Get List" with the filter of "title eq <letter>" to dynamically look up the matching ID of a given letter (e.g. Letter 'C' would return '3'). Then, to increment to the next available letter I use the expression add(1,items('Apply_to_each')?['ID']) to increment to the next available ID. 

 

Finally, I use a Get Item action with the newly incremented ID to find the letter which maps to the new integer.

View solution in original post

5 REPLIES 5
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Frequent Visitor

I found a way to do this using a lookup list of the alphabet and incrementing on the ID value.

Thanks

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Hi @donAlto 

 

Create an array of alphabets as a variable and then get the value using index

0 - A

1- B

...

25 - Z

 

Capture.PNG

 

Regards,

Reza Dorrani

 

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly

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Hi @donAlto , 

 

Could you please share more details about your solutions so we could learn from the solution?

 

And if your problem has been solved, please go ahead and mark the post as solved by clicking “Accept as Solution” so that this thread will be marked for other users to easily identify!

 

Best Regards,

Alice

 

Community Support Team _ Alice Zhang
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

 

 

Highlighted

@RezaDorrani I like your solution.

One issue. I also need to be able to determine the current index of a given letter, so i need:

 

a) Lookup letter by index (your solution)

b) Lookup index by letter (???)

 

Is it still possible to use the array and do B as well?

Highlighted

The idea from @RezaDorrani was more appealing to me as it obscurs the lookup list from a curious user but I could not get it to work lookup both on the ID and the Title (string). Instead I used an old fashioned approach of using a SP List with two columns

ID / Title

1 / A

2 / B

3 / C

etc.

 

Then I used the action "Get List" with the filter of "title eq <letter>" to dynamically look up the matching ID of a given letter (e.g. Letter 'C' would return '3'). Then, to increment to the next available letter I use the expression add(1,items('Apply_to_each')?['ID']) to increment to the next available ID. 

 

Finally, I use a Get Item action with the newly incremented ID to find the letter which maps to the new integer.

View solution in original post

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