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## Scheduled flow to check for last day of the month in a condition

I need a condition to check if tomorrow's day value is less than today's day value (aka 28th/30th/31st -> 1st). I have a bloated workaround to check for is today the 28th in Feb, 30th in months that end in 30 days, and 31st for months that end in 31 but I think this is a lot cleaner.

My current condition is:

`addDays(utcNow('dd'),1)`

is less than

`utcNow('dd')`

The first code snippet is the issue. I don't know how to pull tomorrow's day value correctly.

1 ACCEPTED SOLUTION

Accepted Solutions
Solution Sage

Hi @MitchC3
You can use the expression below to get tommorrow's day value.
Compare this with todays day value
dayOfMonth(utcNow())

Also, should you need it, I think its possible to get the end of the month using the following expression

Did I answer your question? Mark my post as a solution!

Or on LinkedIn at in/leejharris

6 REPLIES 6
Solution Sage

Hi @MitchC3
You can use the expression below to get tommorrow's day value.
Compare this with todays day value
dayOfMonth(utcNow())

Also, should you need it, I think its possible to get the end of the month using the following expression

Did I answer your question? Mark my post as a solution!

Or on LinkedIn at in/leejharris

Anonymous
Not applicable

So this is last day of the month? Is this work perfectly?

Is this work good if month of days is 28 or 29 or 30 or 31?

Also, should you need it, I think its possible to get the end of the month using the following expression

Solution Sage

Hi @Anonymous

Yes, this expression should get you the end of the current month regardless of the number of days in the month.

If we break it down you can see how it is working.

First we get the current date using utcNow(). For this example lets say that the date is 20/01/20.

Then we get the start of the current month using startOfMonth() which gives us 01/01/20.

We then use the addDays() function to add enough days to move into the next month. In this case we are using 32 but you could use anything up to 57. This gives us the date 01/02/20.

Then we use the startOfMonth() function a second time to ensure we are at the beginning of next month which gives us 01/02/20.

Finally, to get the end of the current month we use the addDays() function a second time but use a value of -1 to subtract a single day giving us 31/01/20.

Hope that helps.

Did I answer your question? Mark my post as a solution!

Or on LinkedIn at in/leejharris

Anonymous
Not applicable

Hi @LeeHarris,

This answer is very helpful, thanks! 🙂

Great and so helpful! thx👍

That was hands down one of the BEST replies on here I have seen in a long time, bravo for breaking that down!

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